Formatted Numbers

Read an integer variable and print it in which the digits are separated into groups of three by commas.

Input

The input will contain an integer $A$ ($0 \le A < 200000000$).

Output

Print the formatted number.

Sample

Input	Output
1171123	1,171,123

Solution

Python

import numpy as np

a=input()

n=len(a)
x=[0]*n
a=int(a)
for i in range(0,n):
    f=a//1000
    r=a%1000
    
    if r!=0:
        x[i]=r
        a=f
x=np.trim_zeros(x)
x.reverse()
p=",".join(str(i) for i in x)
print (p)

C++

#include<bits/stdc++.h>
using namespace std;

int main()
{
    string s;
    while(cin>>s)
    {
        int len=s.length();
        for(int i=0; i<len; i++)
        {
            if((len-i)%3==0 && i>0)
                cout<<",";
            cout<<s[i];
        }
        cout<<endl;
    }
    return 0 ;
}

C

#include<stdio.h>
#include<string.h>

int main()
{
    char s[20];
    int i;
    gets(s);
    int k=0,j=0;
    int new[30];
    for(i=strlen(s)-1;i>=0;i--)
    {
        if(j==3)
        {
            new[k++]=',';
            new[k++]=s[i];
            j=0;
        }
        else
            new[k++]=s[i];
     j++;

    }

    for(i=k-1;i>=0;i--)
    {
        printf("%c",new[i]);
    }
}